Dim bPicData() As Byte\n ...\n bPicData = rsMemo("Memo")

\n  private System.Windows.Forms.PictureBox pictureBox_Foto;\n........... \n//Вытаскивание фото \n                byte[] result = null;\n........................\n\nresult = (byte[])dr.GetValue( 0 );\n                        // We cannot assign a byte array directly to an image. \n                        // We use MemoryStream, an object that creates a file in memory\n                        //  and than we pass this to create the image object.\n                        MemoryStream ms = new MemoryStream(result,  0 , result.Length);\n                        Image im = Image.FromStream(ms);\n\n                        pictureBox_Foto.Image = im;\n                        pictureBox_Foto.Visible = true;\n                        pictureBox_Foto.Enabled = true;\n                        pictureBox_Foto.Show();