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Help me, please!
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#18+
Почему в ВБ 6.0 делать абдэйт данных из БД в две разные таблицы последовательно как показоно ниже: 1) Set cmd.ActiveConnection = cn cmd.CommandText = "UPDATE Lei SET Income_in_Lei=? WHERE MainID=?" cmd.CommandType = adCmdText cmd.Prepared = True Set p1 = cmd.CreateParameter("Income_in_Lei", adVarWChar, adParamInput, Len(dIncome), dIncome) cmd.Parameters.Append p1 Set p4 = cmd.CreateParameter("MainID", adVarWChar, adParamInput, Len(Trim(Str(nMainID))), Trim(Str(nMainID))) cmd.Parameters.Append p4 cmd.Execute 2) Set cmd.ActiveConnection = cn cmd.CommandText = "UPDATE Lei SET Income_in_Dol=? WHERE MainID=?" cmd.CommandType = adCmdText cmd.Prepared = True Set p1 = cmd.CreateParameter("Income_in_Dol", adVarWChar, adParamInput, Len(dIncome), dIncome) cmd.Parameters.Append p1 Set p4 = cmd.CreateParameter("MainID", adVarWChar, adParamInput, Len(Trim(Str(nMainID))), Trim(Str(nMainID))) cmd.Parameters.Append p4 cmd.Execute Первый без проблем - все впорядке, а второй дает ошибку типа: "Multiple-step OLE DB peration enerated error. Check each OLE DB tatus value, if avalable. No work was done." Что неправельно я делаю? подскажите кто знает. ... |
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24.04.2003, 15:54 |
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Help me, please!
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#18+
kak ja ponimaju cmd - eto Command object, togda posle 1 -ogo update poprobuite Set cmd = Nothing Set cmd = New ADODB.Command u Microsofta napisano: If two or more Command objects are executed on the same connection ... To execute each Command object, use separate connections or disconnect all other Command objects from the connection. ... |
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24.04.2003, 22:02 |
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