select F1,F2,count(distinct status) ... group by F1,F2 having count(distinct status) = 1

 select status, f1, f2
  from (select status, f1, f2,
               count(distinct status) over (partition by f1, f2) cnt  
          from (select 'OLD' status, 1 f1, 2 f2 from dual
                union
                select 'NEW' status, 1 f1, 2 f2 from dual
                union
                select 'OLD' status, 3 f1, 4 f2 from dual
                union
                select 'NEW' status, 3 f1, 5 f2 from dual) t
       )        
 where cnt=1