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17.01.2016, 22:01
#39149195
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Пытаюсь реализовать Spring Security
переходит на адрес http://localhost:8080/myproject/j_spring_security_check
HTTP Status 404
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<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form"%>
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c"%>
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8" />
<link rel="stylesheet" type="text/css" href="resources/css/style.css" />
<link rel="stylesheet" type="text/css" href="myproject/resources/js/style.css" />
<link rel="shortcut icon" type="image" href="http://localhost:8080/myproject/resources/icons/smile.ico"/>
<script type="text/javascript" src="myproject/resources/js/validation.js"></script>
</head>
<body>
<div class="container">
<header>
<h1>Login</h1>
</header>
<% if (((String)session.getAttribute("NoAuthorization"))!=null) { %>
<div class="alert alert-error">
<div>
<strong>Okay, Houston, we've had a problem here.</strong>
</div>
<ul>
<li>Unknown user or invalid password.</li>
</ul>
</div>
<% } %>
<form class="form-horizontal" action="<c:url value="/j_spring_security_check"></c:url>" method = "POST">
<fieldset>
<div class="control-group">
<label class="control-label">Login</label>
<div class="controls">
<div class="input-prepend">
<span class="add-on">@</span>
<input id="j_username" name="j_username" class="span3" type="text" />
</div>
</div>
</div>
<div class="control-group">
<label class="control-label">Password</label>
<div class="controls">
<input id="j_password" name="j_password" class="span3" type="password" />
</div>
</div>
<div class="form-actions">
<button id="loginButton" name="loginButton" class="btn btn-primary"
type="submit" >Login</button>
</div>
</fieldset>
</div>
</body>
</html>
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<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-4.0.xsd">
<http auto-config="true" use-expressions="true">
<intercept-url pattern="/products/*" access="hasAnyRole('admin','user')" />
<intercept-url pattern="/products**" access="hasAnyRole('admin','user')" />
<intercept-url pattern="/products/create*" access="hasAnyRole('admin')" />
<intercept-url pattern="/products/*/*" access="hasAnyRole('admin')" />
<access-denied-handler error-page="/403" />
<form-login
login-page="/login2"
default-target-url="/products"
authentication-failure-url="/login2?error"
username-parameter="j_username"
password-parameter="j_password" />
<logout logout-success-url="/logout" />
</http>
<!-- Select users and user_roles from database -->
<authentication-manager>
<authentication-provider>
<jdbc-user-service data-source-ref="dataSource"
users-by-username-query=
"select login,password,enabled from users where login=?"
authorities-by-username-query=
"select login, role from users where login =? " />
</authentication-provider>
</authentication-manager>
</beans:beans>
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@RequestMapping(value = "/login2", method = RequestMethod.GET)
public String loginGet(Model model, HttpSession session,
HttpServletRequest request,@RequestParam(value = "error", required = false) String error) {
if (session.getAttribute("NoAuthorization") != null)
model.addAttribute("NoAuthorization", "true");
else
model.addAttribute("NoAuthorization", "false");
if (error != null) {
model.addAttribute("error", "Invalid username and password!");
}
model.addAttribute("url", request.getContextPath());
return "login2";
}
База на Mysql
login password role enabled
Alex 123 admin 1
Kate 123 user 1
Andrew 123 admin 1
Vasa 123 user 1 |
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