В описании класса PipeInputStream написано:



Может кто пояснит фразу: Attempting to use both objects from a single thread is not recommended, as it may deadlock the thread. ?
Ведь при работе с одним потоком команды выполняются последовательно, и взаимной блокировки двух методов не может быть? Или здесь под deadlock подразумевается что то другое?

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A piped input stream should be connected to a piped output stream; the piped input stream then provides whatever data bytes are written to the piped output stream. Typically, data is read from a PipedInputStream object by one thread and data is written to the corresponding PipedOutputStream by some other thread. Attempting to use both objects from a single thread is not recommended, as it may deadlock the thread. The piped input stream contains a buffer, decoupling read operations from write operations, within limits. A pipe is said to be broken if a thread that was providing data bytes to the connected piped output stream is no longer alive.