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#18+
You should implement a simple directory viewer, which should be made by requerements: 1) Directory viewer have a simple UI, which allows user to specify any directory path and should have a button “Build a directory tree”; 2) After pressing of “Build a directory tree” button you application should build a tree of objects in memory. Each element in file system will be a separate node in the tree of objects. Your application also should print your objects tree into xml file; 3) XML file should have the next structure: <directory name=”Some.root.name”> <directory name=”name1”> <file name=”notes1” extention=”txt” /> <file name=”notes2” extention=”txt” /> <file name=”notes3” extention=”txt” /> </directory> <file name=”photo” extention=”jpg” /> </directory> ... |
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| 31.01.2013, 13:30:53 |
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#18+
10% от следующей годовой зарплаты. ... |
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| 31.01.2013, 13:38:13 |
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#18+
Leonidv, ну хоть наведи пример. ... |
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| 31.01.2013, 13:41:17 |
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