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#18+
Как одним запросом получить такой результат: create view cvSums as SELECT Sum(datTickets.PhotoLargeQty) AS [Sum-PhotoLargeQty] FROM datTickets GROUP BY datTickets.Date select max([Sum-PhotoLargeQty]) FROM cvSums ... |
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| 12.08.2004, 15:25:00 |
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#18+
Предлагаю попробовать: SELECT TOP 1 Sum(datTickets.PhotoLargeQty) AS Sum-PhotoLargeQty FROM datTickets GROUP BY datTickets.Date ORDER BY Sum-PhotoLargeQty DESC ... |
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| 12.08.2004, 15:34:03 |
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#18+
PS: Но я сам не пробовал ... |
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| 12.08.2004, 15:35:11 |
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#18+
select max([Sum-PhotoLargeQty]) FROM ( SELECT Sum(datTickets.PhotoLargeQty) AS [Sum-PhotoLargeQty] FROM datTickets GROUP BY datTickets.Date ) AS datTickets1 Я тож сам не пробовал. ... |
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| 12.08.2004, 15:44:50 |
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