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Форумы / ADO.NET, LINQ, Entity Framework, NHibernate, DAL, ORM [игнор отключен] [закрыт для гостей] / множественный выбор в Ole / 2 сообщений из 2, страница 1 из 1
07.12.2006, 06:26
    #34181952
nizar
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Скрыть профиль Поместить в игнор-лист Сообщения автора в теме
множественный выбор в Ole
Подскажите как реализовать? выбрать через OLE
в Table записи выбираемые следующим образом:

"select kc,kvo,sum([sum]) as s150,0 as s259,0 as s421,0 as s422,0 as s445,0 as s448,0 as s449,0 as s453,0 as s457,0 as s465,0 as s479,0 as s480,0 as s580,0 as s581,0 as s582 from zp103 where kvo='150' group by kc,kvo";

"select kc,kvo,0 as s150,sum([sum]) as s259,0 as s421,0 as s422,0 as s445,0 as s448,0 as s449,0 as s453,0 as s457,0 as s465,0 as s479,0 as s480,0 as s580,0 as s581,0 as s582 from zp103 where kvo='259' group by kc,kvo";

"select kc,kvo,0 as s150,0 as s259,sum([sum]) as s421,0 as s422,0 as s445,0 as s448,0 as s449,0 as s453,0 as s457,0 as s465,0 as s479,0 as s480,0 as s580,0 as s581,0 as s582 from zp103 where kvo='421' group by kc,kvo";
и т.д.
...
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07.12.2006, 06:31
    #34181956
nizar
Гость
Скрыть профиль Поместить в игнор-лист Сообщения автора в теме
множественный выбор в Ole
а далее

select kc,
sum(s150) as s150,
sum(s259) as s259,
sum(s421) as s421,
sum(s422) as s422,
sum(s426) as s426,
sum(s427) as s427,
sum(s445) as s445,
sum(s448) as s448,
sum(s449) as s449,
sum(s453) as s453,
sum(s457) as s457,
sum(s465) as s465,
sum(s479) as s479,
sum(s480) as s480,
sum(s580) as s580,
sum(s581) as s581,
sum(s582) as s582

from Table
...
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Форумы / ADO.NET, LINQ, Entity Framework, NHibernate, DAL, ORM [игнор отключен] [закрыт для гостей] / множественный выбор в Ole / 2 сообщений из 2, страница 1 из 1
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